2x^2+15x=x-5

Solution for 2x^2+15x=x-5 equation:

2x^2+15x=x-5

We move all terms to the left:

2x^2+15x-(x-5)=0

We get rid of parentheses

2x^2+15x-x+5=0

We add all the numbers together, and all the variables

2x^2+14x+5=0

a = 2; b = 14; c = +5;
Δ = b2-4ac
Δ = 142-4·2·5
Δ = 156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{156}=\sqrt{4*39}=\sqrt{4}*\sqrt{39}=2\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{39}}{2*2}=\frac{-14-2\sqrt{39}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{39}}{2*2}=\frac{-14+2\sqrt{39}}{4}
$